Notes

1Consider a peak at position d*. If there are [Delta]N peaks per unit d*, then the probability of finding a peak at [d^*+\delta d^*] may be determined by dividing the separation [\delta d^*] into m equal segments [epsilon] ([\delta d^* = m\varepsilon]). The probability, [p(\delta d^*)\varepsilon], of the peak being at [d^*+\delta d^*] is the product of the probabilities of it not being at any of the intermediate segments and then being at [d^*+\delta d^*]. This is given by [p(\delta d^*)\varepsilon = (1-\varepsilon \Delta N)m(\varepsilon \Delta N)]. Since [(1-x/m)m \rightarrow \exp(-x)] as [m\rightarrow \infty], then [p(\delta d^*) = (\Delta N) (1-\varepsilon \Delta N)m = (\Delta N) [1-(\delta d^*\Delta N)/m]{}^m] may be written as [p(\delta d^*) = (\Delta N)\exp(-\Delta N\delta d^*)].