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Acta Cryst. (2004). E60, o1967-o1969 [ doi:10.1107/S1600536804024547 ]
Abstract: A co-crystal of quinol and pyridine would be expected to form with 1:2 stoichiometry because quinol has two hydrogen-bond donors and pyridine has one hydrogen-bond acceptor which is more basic than phenolic oxygen. We report the structure of a 1:1 co-crystal, viz. quinol-pyridine (1/1), C6H6O2·C5H5N, which does not conform to this expectation. Its stability appears to imply that a combination of individually relatively weak C-H
O, C-H![[pi]](/logos/entities/pi_rmgif.gif)
and - stacking interactions are energetically competitive with O-HN hydrogen bonds. Quinol molecules lie on inversion centres, while pyridine is in a general position.
Online 9 October 2004
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