Acta Cryst. (2008). E64, o2225 [ doi:10.1107/S1600536808034764 ]
Abstract: In the title compound, C19H22N3O+·Br-, the imidazole ring is approximately coplanar with the pyridine ring [dihedral angle = 0.88 (13)°] and nearly perpendicular to the benzene ring [dihedral angle = 81.70 (13)°]. O-HBr and C-HBr hydrogen bonding helps to stabilize the crystal structure.
Online 31 October 2008
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