Acta Cryst. (2009). E65, o2086 [ doi:10.1107/S1600536809030219 ]
Abstract: The title compound, C15H13BrN2O2·CH3OH, was synthesized by the reaction of 4-methoxybenzaldehyde with an equimolar quantity of 3-bromobenzohydrazide in methanol. The benzohydrazide molecule displays an E configuration about the C=N bond. The dihedral angle between the two benzene rings is 4.0 (2)°. The benzohydrazide and methanol molecules are linked into a chain propagating along the b axis by O-HO, O-HN, N-HO and C-HO hydrogen bonds.
Online 8 August 2009
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