Crystal data for the double oxides MSbO₄ (M=Cr, Fe)

MSbO₄, (M = Cr, Fe) are tetragonal, rutile-type compounds, P4₂/mnm (No. 136); Z = 1. M and Sb are randomly distributed in 2(a) positions and O in 4(f). For CrSbO₄, D_m = 5.31, D_x = 5.35 Mg m^-1, a = 4.5899 (2), c = 3.0525 (2) Å, U = 64.307 (8) Å³, x = 0.318, R = 4.6; Cr and Sb are coordinated with two O atoms at 2.064 and four O atoms at 1.930 Å.